Question

calculati √2√3+1*√2√3-1
calculati √3*√3+√6*√3-√6
matem clasa a 8 pagina 34ex22

Answer 1

a)√2*√3+1*√2*√3-1=
   √6+√2*√3-1=
   2√6-1=√2*2*6-1=
  √24-1=
  4,89-1=
  3,89≈3,9
b)3+√18-√6=
   3+4,242-2,449=
   3+3√2-√6=
   3+√18-√6=
   7,242-2,229=
   5,013≈5

Answer 2

 [tex]\sqrt2\cdot\sqrt3+1*\sqrt2\cdot\sqrt3-1=\sqrt6+\sqrt6-1=2\sqrt6-1\;;\\ \sqrt3\cdot\sqrt3+\sqrt6\cdot\sqrt3-\sqrt6=3+\sqrt{9\cdot2}-\sqrt6=3+3\sqrt2-\sqrt6\;;\\ [/tex]