Question

Va rog! am nevoie pana luni
Exercitiul 6 si 2
Daca puteti sa imi trimiteti poza

Answer 1

Răspuns:

u=4√6

v=-2√3

a)|v|$^{-1}$ =(2√3)$^{-1}$=$\frac{1}{2\sqrt{3} }$=$\frac{\sqrt{3} }{6}$

b) u·v=4√6·(-2√3)=-8√18=-24√2

c) u:v=$\frac{4\sqrt{6} }{-2\sqrt{3} }$=-2√2

6.

a= $(\frac{2}{\sqrt{3} }-\frac{3}{2\sqrt{3}}+ \frac{1}{3\sqrt{3}}) :\frac{5}{\sqrt{3}}$ =$(\frac{12}{6\sqrt{3}}-\frac{9}{6\sqrt{3}}+\frac{2}{6\sqrt{3}}):\frac{5}{\sqrt{3}}$ = $\frac{5}{6\sqrt{3}} :\frac{5}{\sqrt{3}}$ = $\frac{1}{6}$

=> $a^{-1}$=6 ∈N