Question

calculati (√2-√3)^2-(√2-1)(√2+1)+√24

Answer 1

${( \sqrt{2} - \sqrt{3} )}^{2} - ( \sqrt{2} - 1)( \sqrt{2} + 1) + \sqrt{24}$

$= 2 - 2 \sqrt{6} + 3 - 2 + 1 + 2 \sqrt{6}$

$= 4$