Question

calculati 
(2√7-3√2)² si (3√3-2√3)²

Answer 1

4*7-6radical din 14-6radical din 14+9*2=28-12radical din 14+8=36-12radical din 14

Answer 2

1.
1)2$\sqrt{7}$=$\sqrt{ 2^{2}* 7}$=$\sqrt{28}$
2)3$\sqrt{2}$=$\sqrt{ 3^{2}*2 }$=$\sqrt{18}$
3)$\sqrt{28}$-$\sqrt{18}$=1,048861935....
4)$1,048861935^{2}$=1,1001113587...
2.
1)3$\sqrt{3}$=$\sqrt{ 3^{2}*3 }$=$\sqrt27}$
2)2$\sqrt{3}$=$\sqrt{ 2^{2}*3 }$=$\sqrt{12}$
3)$\sqrt{27}$-$\sqrt{12}$=1,7320508076...
4)$\sqrt{1,7320508076}$=3,0000000001...

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