Question

calculati 2^x + 4^x-1 + 8^x-2 = 9
3ln^2x^2+lnx-1=0
2+cos4x=2sin^2x

Answer 1

2^x+4^x-1+8^x-2=9
3ln^2x^2+lnx-1=0
2+cos4x=2sin^2x
2^x$x^{2}$ 9+2
2^x+4^x=11
8x=16
x=16:8
x=2