Question

Calculați:
27^101:{(3^10×3^15)^12+(9^7:3^4)^30+[(3^2×3^3)^10]^6}​

Answer 1

27^101:{(3^10×3^15)^12+(9^7:3^4)^30+ [(3^2×3^3)^10]^6}=

=27^101:{(3^25)^12+[(3^2)^7:3^4]^30+ [(3^5)^10]^6}=

=27^101:[3^300+(3^14:3^4)^30+(3^50)^60]=

=27^101:[3^300+(3^10)^30+3^300]=

=27^101:(3^300+3^300+3^300)=

=27^101:[3^300×(3^0×30×3^300)=

=27^101:(3^300×3^300)=

=27^101:3^600=

=(3^3)^101:3^600=

=3^303:3^600=

=3^600:3^303=

=3^297