Question

Calculati 2a +3b +c , stiind ca:
a=(5+5;5 +2-2 ;2)x2
b=[36-16;(25;5-12;3)];5-4
c=7+3x[2-27:(5x5+2;1)]

Answer 1

$a=(5+5:5+2-2:2)*2 \\ a=(5+1+2-1)*2 \\ a=7*2 \\ a=14 \\ b=[36-16:(25:5-12:3)]:5-4 \\ b=[36-16:(5-4)]:5-4 \\ b=(36-16:1):5-4 \\ b=(36-16):5-4 \\ b=20:5-4 \\ b=4-4 \\ b=0 \\ c=7+3[2-27:(5*5+2:1)] \\ c=7+3(2-27:27) \\ c=7+3(2-1) \\ c=7+3 \\ c=10 \\ 2a+3b+c=2*14+3*0+10=28+0+10=38$