Question

calculati:(2intreg si 3/6+3 intreg 7/24):(4intreg 2/3 si 1intreg 1/8)

Answer 1

(15/6+79/24):(14/3+9/8)
(60/24+79/24):(112/24+27/24)
139/24:139/24=1

Answer 2

$(2\frac{3}{6}+3\frac{7}{24}):(4\frac{2}{3}+1\frac{1}{8})=\\ =(2+3+\frac{1}{2}+\frac{7}{24}):(4+1+\frac{2}{3}+\frac{1}{8})=\\ =(5+\frac{19}{24}):(5+\frac{19}{24})=\;1\;$