Question

Calculați:3^1x3^2x3^3x...x3^20​

Answer 1

${3}^{1} \times {3}^{2} \times {3}^{3} \times ... \times {3}^{20} = \\ {3}^{1 + 2 + 3 +... + 20} = \\ {3}^{20 \times 21 \div 2} = {3}^{210}$

Answer 2

 

$\displaystyle\bf\\3^1\cdot3^2\cdot3^3\cdot ~...~\cdot 3^{20}=\\\\3^{1+2+3+...+20}\\\\1+2+3+...+20=\frac{20\cdot21}{2}=10\cdot21=210\\\\ 3^1\cdot3^2\cdot3^3\cdot ~...~\cdot 3^{20}=3^{1+2+3+...+20}=\boxed{\bf3^{210}}$