Question

Calculati 3^2-16^12: (4^2•2^11) ^3+1^2003+(2^3•3^2): (2•3)

Answer 1

${3}^{2} - {16}^{12} \div ( {4}^{2} \times {2}^{11} )^{3} + {1}^{2003} + ( {2}^{3} \times {3}^{2}) \div (2 \times 3) = \\ \\ {3}^{2} - {16}^{12} \div (( {2}^{2} ) ^{2} \times {2}^{11} )^{3} + 1 + ( {2}^{2} \times {3}^{1} ) = \\ \\ {3}^{2} - {16}^{12} \div ( {2}^{4} \times {2}^{11} )^{3} + 1 + (4 \times 3) = \\ \\ {3}^{2} - {16}^{12} \div ({2}^{15} )^{3} + 1 + 12 = \\ \\ {3}^{2} - {16}^{12} \div {2}^{45} + 1 + 12 = \\ \\ {3}^{2} - ( {2}^{4} )^{12} \div {2}^{45} + 1 + 12 = \\ \\ {3}^{2} - {2}^{48} \div {2}^{45} + 1 + 12 = \\ \\ {3}^{2} - {2}^{3} + 1 + 12 = \\ \\ 9 - 8 + 1 + 12 = \\ \\ 1 + 1 + 12 = 14$