Question

Calculati: 3^2+3^2•[(3^6)^9:3^51+3•3^35:3^34]:9^2. Trebuie sa dea 13. Coroana!!!

Answer 1

$3^2+3^2\cdot\Big[{\big(3^6\big)}^9:3^{51}+3\cdot3^{35}:3^{34}\Big]:9^2 = \\ \\ = 9+3^2\cdot \big(3^{6\cdot 9} :3^{51}+3\cdot 3^{35-34}\big):9^2 = \\ \\=9 +3^2\cdot \big(3^{54}:3^{51}+3\cdot 3\big):9^2 = \\ \\ = 9+3^2\cdot \big(3^{54-51}+3^2\big):{(3^2)}^2 = \\ \\ = 9+3^2\cdot \big(3^3+3^2\big):3^4 = \\ \\ = 9+(3^5+3^4):3^4 = \\ \\ = 9+3^5:3^4+3^4:3^4 = \\ \\ = 9+3+1 = \\ \\ = 13$

Answer 2

3²+3²x[(3⁶)⁹:3⁵¹+3x3³⁵:3³⁴]:(3²)²=
3²+3²x(3⁵⁴:3⁵¹+3x3³⁵:3³⁴):3⁴=
3²+3²x(3⁵⁴⁻⁵¹+3x3³⁵⁻³⁴):3⁴=
3²+3²x(3³+3x3):3⁴=
3²+3²x(3³+3²):3⁴=
3²+3²x3²(3+1):3⁴=
3²+3⁴x4:3⁴=
3²+4x3⁴:3⁴=3²+4x3⁰=3²+4x1=9+4=13