Question

Calculati
(√3 +i) la puterea 6

Answer 1

Răspuns:

-64

Explicație pas cu pas:

(√3+i)^6=(3+2i√3-1)^3=(2+2i√3)^3=2^3*(1+i√3)^3=8*(1+i√3)^2*(1+i√3)=8*(1+2i√3-3)*(1+i√3)=8*(2i√3-2)(i√3+1)=16(i√3-1)(i√3+1)=16*(-3-1)=-64

unde i^2=-1