Question

calculati 3la puterea 2 -2 la puterea 3)totul la puterea 2010

Answer 1

3²-2³)²⁰¹⁰=(9-8)²⁰¹⁰=1²⁰¹⁰=1
2⁷/4³·27/3⁵+(3¹·2⁴-4²)/2³=
2⁷/(2²)³·3³/3⁵+(3·16-16)/2³=
2⁷/2⁶·3³⁻⁵+(48-16)/2³=
2⁷⁻⁶·3⁻²+32/8=
2/9+4=(2+36)/9=38/9

125x1111³-5555³=125x1111³-(5x1111)³=
125x1111³-5³x1111³=125x1111³-125x1111³=
125x1111³(1-1)=125x1111³x0=0

9⁵-(3⁵)²+8⁴-(2⁴)³=
(3²)⁵-3¹⁰+(2³)⁴-2¹²=
3¹⁰-3¹⁰+2¹²-2¹²=0

Answer 2

$( 3^{2} - 2^{3}) ^{2010} = (9-8)^{2010} = 1^{2010} =1$
si gata :)