Question

-Calculaţi:4,8^2-1,2{11+1,1× [6,9+2×(3,24 -3,19)]}​

Answer 1

Răspuns:

4,8^2-1,2{11+1,1× [6,9+2×(3,24 -3,19)]}​=

23,04-1,2[11+1,1(6,9+2·0,05)]=

23,04-1,2[11+1,1(6,9+0,1)]=

23,04-1,2(11+1,1·7)=

23,04-1,2(11+7,7)=

23,04-1,2·18,7=

23,04-22,44=

0,6

Answer 2

4, 8 ^ 2 - 1, 2 × { 11 + 1, 1 × [ 6, 9 + 2 × ( 3, 24 - 3, 19 ) ] } =

23, 04 - 1, 2 × [ 11 + 1, 1 × ( 6, 9 + 2 × 0, 05 ) ] =

23, 04 - 1, 2 × [ 11 + 1, 1 × ( 6, 9 + 0, 1 ) ] =

23, 04 - 1, 2 × ( 11 + 1, 1 × 7 ) =

23, 04 - 1, 2 × ( 11 + 7, 7 ) =

23, 04 - 1, 2 × 18, 7 =

23, 04 - 22, 44 = 0, 6