Question

calculati: 4radical12-radical27+radical75=xradical3
ajutor :)

Answer 1

$4\sqrt{12} - \sqrt{27} + \sqrt{75} =x \sqrt{3}$

$4 \sqrt{12} =4*2 \sqrt{3} =8 \sqrt{3}$

$\sqrt{27} = 3\sqrt{3}$

$\sqrt{75}=5 \sqrt{3}$

$8\sqrt{3} - 3\sqrt{3} +5 \sqrt{3} =x \sqrt{3}$

$10\sqrt{3} =x \sqrt{3}$  ⇒ x=10