Question

Calculati : 4sin 30 grade-6cos60 grade +5tg45 grade

Answer 1

   
[tex]\displaystyle \\ 4\sin 30^o - 6\cos60^o + 5 \text{tg} \,45^o = \\ \\ = 4 \times \frac{1}{2} - 6 \times \frac{1}{2} + 5 \times 1 = \\ \\ =2-3+5 = \boxed{4}[/tex]

Answer 2

S= 4•1/2 - 6•1/2 + 5•1=
= -2•1/2 +5 =
= -2/2 -5 =
= -1 +5 =
= 4