Question

Calculați:
(7^14×5)^2÷7^26=
(7^6)^8÷49^24=
(3^4)^9÷(9^6)^3=
(11^2011×4^1005)÷[(22^2)^5]^201=
2^23÷2^21÷2+3^32÷3^31×3=

Answer 1

(7^14 x 5)^2 : 7^26 = 7^28 x 25 : 7^26 = 7^2 x 25 = 49 x 25 = 1225

(7^6)^8 : 49^24 = 7^48 : (7^2)^24 = 7^48 : 7^48 = 1

(3^4)^9 : (9^6)^3 = 3^36 : 9^18 = 3^36 : (3^2)^18 = 3^36 : 3^36 = 1

(11^2011 x 4^1005) : [(22^2)^5]^201 = [11^2011 x (2^2)^1005] : {[(2x11)^2]^5]^201} = (11^2011 x 2^2010) : (2x11)^2010 = (11^2011 x 2^2010) : (2^2010 x 11^2010) = 11

2^23 : 2^21 : 2 + 3^32 : 3^31 x 3 = 2^(23-21-1) + 3^(32-31+1) = 2^1 + 3^2 = 2 + 9 = 11