Question

calculati:
8+6x[4+27/(0+ux9)]=49+10/10

Answer 1

$8+6(4+ \frac{27}{9u} )=49+1$

$6(4+ \frac{27}{9u} )=50-8$

$6(4+ \frac{27}{9u} )=42$

$4+ \frac{27}{9u} = \frac{42}{6}$

$4+ \frac{27}{9u} = 7$

$\frac{27}{9u} =7-4$

$\frac{27}{9u} =3$

$3*9u=27$

$27u=27$

$u= \frac{27}{27}$

$u=1$