Question

Calculati :
a) 0,(3):4supra5-1supra2:1(3)=
b) 1pe4·(3+3:2supra0,(6)=
c) 11,4:0,6-0,7·0,09-4,1·0,07=
d) 2,4·8,6-1,6:0,2+3,4·4,8=
e) 6,4·(1,28+1,6·3,2)=
f) 2 1pe9·1 4pe5+0,1(6)=
g) 21 1pe5:(7,2-3 1pe10+6,5)+0,(6)=

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Answer 1

a) 0,(3):4/5-1/2:1(3)= 3/9 x 5/4 - 1/2:(13-1)/9 = 1/3x5/4 - 1/2 : 12/9 = 5/12 - 1/2:4/3 = 5/12 - 1/2 x 3/4 = 5/12 - 3/8 = 10/24 - 9/24 = 1/24
b) 1/4x(3+3:2/0,(6)= 1/4 x [3+3:2/(6/9)] = 1/4 x [3+3:2/(2/3)] = 1/4 x [3+3:(2x3/2)] = 
1/4 x (3+3:3) = 1/4 x (3+1) = 1/4 x 4 = 1
c) 11,4:0,6-0,7x0,09-4,1x0,07= 114/10 : 6/10 - 7/10 x 9/100 - 41/10 x 7/100 = 114/10x10/6 - 63/1000 - 287/1000 = 114/6 -63/1000 - 287/1000 = 19 - 63/1000 - 287/1000 = 19000/1000 - 63/1000 - 287/1000 = (19000-63-287)/1000 = 18650/1000 = 18,65
d) 2,4x8,6-1,6:0,2+3,4x4,8= 24/10 x 86/10 - 16/10 : 2/10 + 34/10 x 48/10 = 12/5x43/5 - 16/10 x 10/2 + 17/5 x 24/5 = 516/25 - 16/2 + 408/25 = 516/25-8+408/25 = 516/25 - 200/25 + 408/25 = (516-200+408)/25 = 724/25 = 2896/100 = 28,96
e) 6,4x(1,28+1,6x3,2)= 64/10 x (128/100 + 16/10 x 32/10) = 64/10 x (128/100 + 512/100) = 64/10 x 640/100 = 40960/1000 = 40,96 
f) 2 si 1/9x1 si 4pe5+0,1(6)= 19/9 x 9/5 + (16-1)90 = 19/5 + 15/90 = 19/5 + 1/6 = 114/30 + 5/30 = 119/30 = (90+29)/30 = 90/30 + 29/30 = 3 si 29/30
g) 21 si1 pe5:(7,2-3 si 1pe10+6,5)+0,(6)= 106/5 : (72/10 - 31/10+65/10) + 6/9 = 106/5 : 106/10 + 2/3 = 106/5 x 10/106 + 2/3 = 2 + 2/3 = 2 si 2/3