Question

Calculati
a. 1 la puterea 2 la puterea 3 + 3 la puterea 1 la puterea 2 + 2 la puterea 3 la puterea 1 (daca puteti va rog sa imi explicati la acest calcul)
b. ( 16 x 12 la puterea 10 - 4 x 12 la puterea 10) : 12 la puterea 11
c.  5 la puterea 11 - ( 6 x 5 la puterea 10 - 2 x 5 la puterea 10)

Answer 1

$a)$
$1^{2^{3}}+3^{1^{2}}+2^{3^{1}}= 1^{8} + 3^{1} + 2^{3} = 1+3+8= 12$
$sau$
$(1^{2})^{3}+ (3^{1})^{2}+ (2^{3})^{1}= 1^{2*3}+ 3^{1*2}+ 2^{3*1} = 1+9+8=18$

$b)$
$(16* 12^{10}-4*12^{10}): 12^{11}=(12 * 12^{10}): 12^{11}=12^{11}:12^{11}=1$

$c)$
$5^{11} -(6* 5^{10}-2* 5^{10})=5* 5^{10}-4*5^{10}=5^{10}$