Question

Calculati: a) 1 supra 2 x 1 supra 3 + 1 supra 2 x 1 supra 5 - 1 supra 2 x 8 supra 15
b) 1 supra 2 x 3 supra 5 + 1 supra 4 + 1 supra 3 + 1 supra 8 x 2 supra 3
c) 5 supra 32 x 3 supra 4 + 5 supra 4 x 3 supra 8
Va rog repedee!

Answer 1

a. (1\2)×(1\3)=1×1supra2×3=1\6
(1\2)×(1\5)=1×1supra2×5=1\10
(1\2×(8\15)=1×4supra1×15=4\15
1\6+1\10=5+3suprau30=8\30, 8\30-4\15=8-8 supra lui30=0\30.

b. (1\2)×(3\5)=1×3supra lui2×5=3\10
(1\8)×(2\3)=1×1supra lui4×3=1\12
3\10+1\4=6+5supra lui20=11\20
11\20+1\3=33+20supra lui60=53\60
53\60+1\12=53+5supra lui60=58\60 apoi simplificam la 2=26\30.

c. (5\32)×(3\4)=5×3supra lui32×4=15\128
(5\4)×(3\8)=5×3supra lui4×8=15\32
15\128+15\32=15+60supra lui 128=75\128.
SPER CA TE-AM AJUTAT!!!