Question

Calculati:
a)[1 supra 4+(5 supra 2 - 1 intreg si 3 supra 4) : 7 supra 8] × 14;
b)[(1 supra 12 + 1 supra 10 + 4 supra 15 ) : 1 supra 15 +2 : 1 supra 18] × 4 supra 11;
c)3 supra 4 × (8 supra 9 - 1 supra 6) : 5 supra 4;
Va rog frumos!

Answer 1

a)[1/4+(5/2 - 7/4)×8/7]×14=
(1/4+3/4×8/7)×14=
(1/4+6/7)×14=
31/28 × 14=
31/2
b)(27/60×15+2×18)×4/11=
(27/4 + 36)×4/11=
171/4 × 4/11=
171/11
c)3/4×13/18×4/5=
13/30