Question

Calculati a^2-1 unde a= [(7/3-11/6-5/2):0,(6)+0,2]:0.05

Answer 1

a = [ ( 7 / 3 - 11 / 6 - 5 / 2 ) : 0,(6) + 0,2 ] : 0,05

a = [ ( 14 / 6 - 11 / 6 - 15 / 6 ) : 6 / 9 + 2 / 10 ] : 5 / 100

a = [ ( - 12 / 6 ) : 2 / 3 + 1 / 5 ] : 1 / 20

a = [ ( - 2 ) x 3 / 2 + 1 / 5 ] : 1 / 20

a = ( - 3 + 1 / 5 ) × 20

a = ( - 15 + 1 ) / 5 × 20

a = ( - 14 ) × 4

a = - 56

a² - 1 = ( -56)² - 1 = 3 136 - 1 = 3 135

Answer 2

$(\frac{14-11-15}{6} :\frac{6}{9} +\frac{12}{10} ) :\frac{1}{20} =$

$= (-2 *\frac{9}{6} +\frac{2}{10} )\frac{20}{1} =$

$= (\frac{-9}{3} +\frac{2}{10})*20 =$

$= (-3 +\frac{2}{10} )*20 =$

$= (-3 + \frac{1}{5} )*20 =$

$=(\frac{-15+1}{5} )*20 =$

$=\frac{-14}{5} * 20 =$$= -14*4 = -56$

$a^{2} - 1 = 3136-1 = 3135$