Question

calculati
a)√2+√50-√32

b)√3(√27+4√3)

c)(√3+2)²-20

d)(√45-√5)²-20

e)3√48-5√3-2√72

f)√2(2√2+√72)

g)3√80+(6-√5)²-40

h)√45-√75
-------------
√3-√5

Answer 1

a)√2+√50-√32 =
=√2+5√2-4√2 =2√2

b)√3(√27+4√3) =
=√81+4√9 =
=9+4x3=
=9+12=21

c) (√3+2)²-20=
=3+4+4√3-20=
=4√3-13

d)(√45-√5)²-20=
=45+5-2√45*5-20=
=50-2*15-20=
=30-30=0

e)3√48-5√3-2√72=
=12√3-5√3-12√2=
=7√3-12√2

f)√2(2√2+√72)=
=4+√144=
=4+12=16

g) 3√80+(6-√5)²-40 =
=12√5+36-12√5+5-40 =
=+36+5-40 =
=41-40=1

h) (√45-√75 )/(√3-√5)=
=(√45-√75)(√3+√5)/(√3-√5)(√3+√5)=
=(√45*3-√75*3+√45*5-√75*5)/(3-5)=
=(3√15-15+15-5√15)/(-2)=
=-2√15/(-2)=
=√15