Question

Calculati :
a. [[ ( 27/25 - 1/2 x 21/25 )] x 25/3 - 1 ] x 3013 - 10 la puterea 3 .
b. ( 65/195 + 108/324 + 122/366) x ( 24/168 - 6/42 )
Dau 20 puncte cine raspunde primul!
x => inmultire
/ => supra
Va rog frumos!!!

Answer 1

a)
{[(27/25-1/2×21/25)] × 25/3 - 1}×3013 - 10^3 =

= [(27/25-21/50)×25/3-1]×3013-1000 =

=[ (27×2/50 - 21/50)×25/3-1]×3013-1000 =

=[ (54/50 -21/50)×25/3 -1 ] × 3013 - 1000 =

= (33/50×25/3-1)×3013-1000 =

= (11/2-1)×3013-1000 =

= (11/2 - 2/2) × 3013-1000 =

= 9/2 × 3013 - 1000 =

= 27117/2 - 1000 =

= 27117/2 - 2000/2 =

= 25117/2 =

= 12558,5


b)
(65/195 + 108/324 + 122/36) × (24/168-6/42) =

= (65/195 + 108/324 + 122/36)×(1/7 - 1/7) =

= (65/195 + 108/324 + 122/36) × 0 =

= 0

in a doua paranteza am simplificat:
24/168 cu 24 = 1/7
6/42 cu 6 = 1/7