Question

Calculati:
a)(2a)^3=
b)(3a^2)^4=
c)(4x^2y^3)^2=
d)(-a^2b^3c)^4=
e)(6x^10y^4z^2)^2=
f)(a^3b^4c/x^2y)^12=
Dau coroana

Answer 1

$a).(2a)^3=2^3a^3=a^8 \\ b).(3a^2)^4=3a^2^*^4=3^4(a^2)^4=81a^2^*^4=81a^8 \\ c).(4x^2y^3)^2=4^2(x^2)^2(y^3)^2=16x^2^*^2y^3^*^2=16x^4y^6 \\ d).(-a^2b^3c)^4=(a^2)^4(b^3)^4c^4=a^2^*^4b^3^*^4c^4=a^8b^1^2c^4 \\ e).(6x^1^0y^4z^2)^2=6^2(x^1^0)^2(y^4)^2(z^2)^2=36x^1^0^*^2y^4^*^2z^2^*^2=36x^2^0y^8z^4$