Question

calculati
a) (2x-5)²+(4x+3)²-(7x-2)(7x+2)=
b) (3-2a)²-(4a+1)²+(4a-5)(4a+5)=
c) (2-√5)²:(9-4√5)+(√3-7)²:(52-14√3)=
d) (2√2-3)²+(4-3√2²)-2(2-3√2)²=
e) (2√3-√5)²+(3√2-7)(3√2+7)+√240=

Answer 1

)a (2x-5)²+(4x+3)²-(7x-2)(7x+2)=
2x²-20x+25+16x²+24x+9-49x²+4=
-31x²+4x-38

b) (3-2a)²-(4a+1)²+(4a-5)(4a+5)=
6-12a+4a²-4a²-8a-1+16a²-25=
16a²-20a-20

c) (2-√5)²:(9-4√5)+(√3-7)²:(52-14√3)=
(4--4√5+5):(9-4√5)+(3-14√3+49):(52-14√3)=
(9-4√5):(9-4√5)+(52-14√3):(52-14√3)=1+1=2

d) (2√2-3)²+(4-3√2)²-2(2-3√2)²=
(8-12√2+9+16-24√2+18-2(4-12√2+18)=
51-36√2-2(22-12√2)=
51-36√2-44+24√2=
7-12√2

e) (2√3-√5)²+(3√2-7)(3√2+7)+√240=
12-4√15+18-49+4√15=-19