Question

Calculați: a) (3-2i) la puterea 2 + (1+2i)la puterea2
b) (2+i)(i-2 conjugat)

Answer 1

a)(3-2i)²+ (1+2i)²=
=9-12i+4i²+1+4i+4i²=
=9-12i-4+1+4i-4=
=-8i+2

b)(2+i)(i-2)=
=(i+2)(i-2)=
=i²-2²=
=-1-4=
=-5

Answer 2

$(3-2i)^{2}+ (1+2i)^{2}=9-12i-4+1+4i-4=2-8i \\ b)=(2+i)(-2-i)=-(2+i)^2=-4-4i+1=-3-4i$