Question

Calculati :
A)3³+ 3²⁰: 3¹⁸ x 3+3x3⁸ : 3⁶ + 3¹⁰ : (8x 3⁵+3⁵)- 4 x 3³

B)[3+3x3⁴³ +(7⁵)¹⁰ :7⁷la puterea 2]: [9²²+7^1²²+15ⁿ⁺¹: 5ⁿ⁺¹ : 3ⁿ]=

C)18²+36:[2⁸la puterea 2 : (-2⁹)⁷ +9¹⁵ : (3x3 ²⁸)]=

E)6+3x[(5¹⁸ x3²²)⁴: (5⁷¹x 3⁸⁶)-9¹²:3²²+24]=


VA ROGGG
DAU COROANA !!

Answer 1

A)3³+ 3²⁰: 3¹⁸ x 3+3x3⁸ : 3⁶ + 3¹⁰ : (8x 3⁵+3⁵)- 4 x 3³=
=3³+ 3² x 3+3x3⁸ : 3⁶ + 3¹⁰ :  3⁵(8+3°)- 4 x 3³=
=3³+ 3³+3x3² + 3¹⁰ :  3⁵x3²- 4 x 3³=
=3³+ 3³+3³ + 3¹⁰ : 3⁷- 4 x 3³=
=3x3³+3³-4x 3³=0


B)[3+3x3⁴³ +(7⁵)¹⁰ :7⁷la puterea 2]: [9²²+7^1²²+15ⁿ⁺¹: 5ⁿ⁺¹ : 3ⁿ]=
=[3+3⁴⁴ +(7⁵⁰ :7⁴⁹]: [3⁴⁴+7+3ⁿ⁺¹ : 3ⁿ]=
=[3+3⁴⁴ +7]: [3⁴⁴+7+3¹]=
=[3⁴⁴ +10]: [3⁴⁴+10]=1

C)18²+36:[2⁸la puterea 2 : (-2⁹)⁷ +9¹⁵ : (3x3 ²⁸)]=
=2²x3⁴+36:[2⁶⁴ : (-2)⁶³ +3³⁰ : 3 ²⁹]=
=2²x3⁴+36:[-2¹+3¹]=
=2²x3⁴+36:1=
=2²x3⁴+2²x3²=
=2²x3²(3²+1)=
=2²x3²x10=
=2³x3²x5

E)6+3×[(5¹⁸ ×3²²)⁴: (5⁷¹× 3⁸⁶)-9¹²:3²²+24]= 
=6+3×[(5⁷² ×3⁸⁸): (5⁷¹× 3⁸⁶)-3²⁴:3²²+24]= 
=6+3×[(5 ×3²)-3²+2³×3]= 
=6+3×[3²(5-1)+2³×3]=
=6+3×[3²×2²+2³×3]=
=6+3×[3×2²(3+2)]=
=6+3×3×2²×5=
=2×3+3²×2²×5=
=2×3×(1+3×2×5)=
=2×3×31