Question

Calculati
a) 5 supra 6 + 2 1 supra 2 • 4 supra 5
b) 2 1 supra 3 • 9 supra 14 - 1 1supra2 • 1 supra 3
c) 10 1 supra 2 - (2 2 supra 3 • 27 supra 32 - 5 supra 8 • 14 supra 32

Answer 1

a)5/6+2intreg1/2x4/5=
5/6+5/2x4/5=
=5/6+2=(5+2x6)/6=
=17/6

b)2intreg 1/3x9/14-1intreg 1/2x1/3=
7/3x9/14-3/2x1/3=simplif=
(7x3)/14-1/2=
3/2-1/2=2/2=1

c)10intreg 1/2-(2 intreg2/3x27/32-5/8x14/32)=
21/2-(8/3x27/32-5/8x14/32)=simplif.ce se poate=
21/2-(9/4-35/128)=
21/2-[(9x32-35)/128]=
21/2-253/128=
(21x64-253)/128=
(1344-253)/128=1091/128