Matematică, întrebare adresată de Mariachivari14, 9 ani în urmă

Calculați:
A) 7 supra 5 +0 ,(81)+3 la puterea 2 • (5-4•1 supra 8)
B)1supra 4 •(2,5 +5 la put. 2)
C)2,(3)+ 1,5•2-1)
D) 1,2 la puterea 2 +3•[4•(2•0,5-1)]
Vă rog!!!

Răspunsuri la întrebare

Răspuns de Utilizator anonim
4
a) \frac{7}{5} + 0.(81) + {3}^{2} \times (5 - 4 \times \frac{1}{8} )

 = \frac{7}{5} + \frac{81}{99} + 9 \times (5 - \frac{4}{8} )

 = \frac{7}{5} + \frac{9}{11} + 9 \times ( 5 - \frac{1}{2} )

 = \frac{7}{5} + \frac{9}{11} + 9 \times ( \frac{10}{2} - \frac{1}{2} )

 = \frac{7}{5} + \frac{9}{11} + 9 \times \frac{10 - 1}{2}

 = \frac{7}{5} + \frac{9}{11} + 9 \times \frac{9}{2}

 = \frac{7}{5} + \frac{9}{11} + \frac{9 \times 9}{2}

 = \frac{7}{5} + \frac{9}{11} + \frac{81}{2}

 = \frac{22 \times 7}{110} + \frac{9 \times 10}{110} + \frac{55 \times 81}{110}

 = \frac{154}{110} + \frac{90}{110} + \frac{4455}{110}

 = \frac{154 + 90 + 4455}{110}

 = \frac{4699}{110}

 = 42.71

b) \frac{1}{4} \times (2.5 + {5}^{2} )

 = \frac{1}{4} \times ( \frac{25}{10} + 25)

 = \frac{1}{4} \times ( \frac{5}{2} + 25)

 = \frac{1}{4} \times ( \frac{5}{2} + \frac{2 \times 25}{2} )

 = \frac{1}{4} \times ( \frac{5}{2} + \frac{50}{2} )

 = \frac{1}{4} \times \frac{5 + 50}{2}

 = \frac{1}{4} \times \frac{55}{2}

 = \frac{1 \times 55}{4 \times 2}

 = \frac{55}{8}

 = 6.875

c)2.(3) + 1.5 \times 2 - 1

 = \frac{23 - 2}{9} + 3 - 1

 = \frac{21}{9} + 3 - 1

 = \frac{7}{3} + 3 - 1

 = \frac{7}{3} + \frac{3 \times 3}{3} - \frac{3 \times 1}{3}

 = \frac{7}{3} + \frac{9}{3} - \frac{3}{3}

 = \frac{7 + 9 - 3}{3}

 = \frac{13}{3}

 = 4.(3)

d) ({1.2})^{2} + 3 \times (4 \times (2 \times 0.5 - 1))

 ={ ( \frac{12}{10 } ) }^{2} + 3 \times (4 \times (1 - 1))

 = \frac{ {12}^{2} }{ {10}^{2} } + 3 \times (4 \times 0)

 = \frac{144}{100} + 3 \times 0

 = \frac{72}{50} + 0

 = \frac{36}{25}

 = 1.44
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