Matematică, întrebare adresată de qmiliard3, 9 ani în urmă

Calculati : a) 8/5-4/5= b) 11/6-7/6= c) -14/3-7/3= d) -7/8-13/8= e)-4/9-(-8/9)= f) -9/7-(-4/7)= g) 7/4-10/8= h) 15/9-10/3= i) -5/4-10/8= j) -7/5-12/30= k) 9/21-(-8/7)= l)-52/24-(-5/6)= m) 8/3-1/2-5/6= n) 3/8-7/2-5/4= o) 1/8-5/1-8/4= p) 1/5-8/3-(-3/15)= q) 7/18-2/9-(11/3)=

Răspunsuri la întrebare

Răspuns de Marina001
5

a) \frac{8}{5}-\frac{4}{5}=\frac{8-4}{5}=\frac{4}{5}

b) \frac{11}{6}-\frac{7}{6}=\frac{11-7}{6}=\frac{11-7}{6}=\frac{2}{3}

c) -\frac{-4}{3}-\frac{7}{3}=\frac{-14-7}{3}=\frac{-21}{3}=-\frac{21}{3}=-7</p><p>[tex]d) -\frac{7}{8}-\frac{13}{8}=\frac{-7-13}{8}=-\frac{20}{8}=-\frac{5}{2}

e)\left(-\frac{4}{9}\right)-\left(-\frac{8}{9}\right)=\frac{-4+8}{9}=\frac{4}{9}

f)\left(-\frac{9}{7}\right)-\left(-\frac{4}{7}\right)=-\frac{9}{7}+\frac{4}{7}=\frac{-9+4}{7}=\frac{-5}{7}=-\frac{5}{7}

g) \frac{7}{4}-\frac{10}{8}=\frac{7}{4}-\frac{5}{4}=\frac{2}{4}=\frac{1}{2}

h) \frac{5}{9}-\frac{10}{3}=\frac{5}{9}-\frac{30}{9}=\frac{-25}{9}=-\frac{25}{9}

i)-\frac{5}{4}-\frac{10}{8}=-\frac{5}{4}-\frac{5}{4}=\frac{-5-5}{4}=\frac{-10}{4}=-\frac{5}{2}

j) -\frac{7}{5}-\frac{12}{30}=-\frac{7}{5}-\frac{2}{5}=\frac{-7-2}{5}=-\frac{9}{5}

k) \left(\frac{9}{21}\right)-\left(-\frac{8}{7}\right)=\frac{9}{21}+\frac{8}{7}=\frac{3}{7}+\frac{8}{7}=\frac{11}{7}

l) \left(-\frac{52}{24}\right)-\left(-\frac{5}{6}\right)=-\frac{52}{24}+\frac{5}{6}=-\frac{13}{6}+\frac{5}{6}=\frac{-13+5}{6}=\frac{-8}{6}=-\frac{4}{3}

m) \frac{8}{3}-\frac{1}{2}-\frac{5}{6}=\frac{16}{6}-\frac{3}{6}-\frac{5}{6}=\frac{8}{6}=\frac{4}{3}

n) \frac{3}{8}-\frac{7}{2}-\frac{5}{4}=\frac{3}{8}-\frac{28}{8}-\frac{10}{8}=\frac{3-28-10}{8}=\frac{-35}{8}=-\frac{35}{8}

o)\frac{1}{8}-\frac{5}{1}-\frac{8}{4}=\frac{1}{8}-5-\frac{8}{4}=\frac{1}{8}-5-2=\frac{1}{8}-7=-\frac{7\cdot \:8}{8}+\frac{1}{8}=\frac{-7\cdot \:8+1}{8}=-\frac{55}{8}

p) \frac{1}{5}-\frac{8}{3}+\frac{3}{15}=\frac{1}{5}-\frac{8}{3}+\frac{1}{5}=\frac{2}{5}-\frac{8}{3}=\frac{6}{15}-\frac{40}{15}=\frac{6-40}{15}=\frac{-34}{15}=-\frac{34}{15}

q) \frac{7}{18}-\frac{2}{9}-\frac{11}{3}=\frac{7}{18}-\frac{4}{18}-\frac{66}{18}=\frac{7-4-66}{18}=\frac{-63}{18}=-\frac{63}{18}

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