Question

calculati:c)[(3^2*3^3+2^54÷2^54+(3^5)^4÷3^20]÷31
va rogggg rapiddd!!!!​

Answer 1

$( {3}^{5} + 1 + {3}^{20} \div {3}^{20} ) \div 31 = ( {3}^{5} + 1 + 1) \div 31 = \frac{ {3}^{5} + 2 }{31} = \frac{245}{31}$