Question

calculati compozitia procentuala masica in elementele a unei solutii de hidroxid de calciu care contine 2% calciu.

Answer 1

M-Ca(OH)2 =40+(16×2)+(1×2)
=40+32+2
=72+2
=74g/mol
74g subst....40gCa....32gO....2gH
100g subst....XgCa....YgO....ZgH
XgCa= 40×100 supra 74
X=4000 supra 74
X=54,05gCa=> Ca(OH)2 are 54,05% Ca
Y=10×32 supra 74
Y=3200 supra 74
Y=43,2gO=> Ca(OH)2 are 43,2%O
Z=100×2 supra 74
Z=200 supra 74
Z=2,7gH=> Ca(OH)2 are 2,7%H
Sper ca te-am ajutat