Question

Calculati concentratia ionilor hidroxid dintr-o solutie de hidroxid de potasiu cu pH=13. Dau coroana, va rog mult!

Answer 1

KOH -> baza tare

pH=13

pH=-lg [H₃O⁺] = -lg 10⁻¹³ = 13

Kw=[OH⁻]*[H₃O⁺] = 10⁻¹⁴ (mol/L)² => [OH⁻] = 10⁻¹⁴/10⁻¹³ = 10⁻¹ mol/L

sau pH + pOH = 14 => pOH = 14-13 = 1

[OH⁻] = 10⁻pOH = 10⁻¹ mol/L