Question

Calculaţi f(-4)+f(4) pentru functia f:R →R,f(x)=x²-16

Answer 1

f(-4)=(-4)^2-16=16-16=0

f(4)=4^2-16=16-16=0

f(-4)+f(4)=0+0=0

Answer 2

$f(x) = {x}^{2} - 16 \\ \\ f( - 4) = - 4 \times ( - 4) = 16 = 16 - 16 = 0 \\ \\ f(4) = 4 \times 4 - 16 = 16 - 16 = 0 \\ \\ Deci \: f(-4)+f(4)=0+0=0$