Question

suma a 3 mr este 243 impartind primul la al 3 obtinem catul 12 si restul 7,iar impartind al doilea la al 3 lea obtinem catul 5 si restul 2 determinati nr.URGENT DAU COROANA

Answer 1

a + b + c = 243 → suma

a : c = 12 rest 7

a = 12 × c + 7

b : c = 5 rest 2

b = 5 × c + 2

a + b + c = 243

( 12 × c + 7 ) + ( 5 × c + 2) + c = 243

( 12 × c + 5 × c + c ) + ( 7 + 2) = 243

18 × c = 243 - 9

c = 234 : 18

c = 13 → al treilea nr.

a = 12 × 13 + 7 = 156 + 7 = 163 → primul numar

b = 5 × 13 + 2 = 65 + 2 = 67 → al doilea numar

Verific: 163 + 67 + 13 = 163 + 80 = 243 → suma celor 3 numere

Raspuns: 163; 67 si 13

Answer 2

a+b+c=243

a/c=cat12rest7, a=12c+7 (teorema impartirii cu rest)

b/c=cat5res2, b=5c+2, inlocuim a si b in suma

12c+7+5c+2+c=243, 18c=243-9=234, c=234/18=13

a=12*13+7=163, b=5*13+2=67