Question

Calculați folosind scoaterea uni factor comun
53×47-53×40+53=
28×13+39×13-12×13=
508+508×9=
209×384+209×216-201×600=
123×53-123×50+3×147=

Answer 1

Răspuns:

53×(47-40+1)=53×(7+1)=53×8=424

13×(28+39-12)=13×(67-12)=13×55=715

508×(1+9)=508×10=5080

209×(384+216)-201×600=209×600-201×600=600×(209-201)=600×8=

4800

123×(53-50)+3×147=123×3+3×147=3×(123+147)=3×270=810

Answer 2

1. 53×(47-40+1)=53×8=424

2. 13×(28+39-12)=13×55=715

3. 508×(1+9)=508×10=5080

4.209×(384+216)-201×600=

209×600-201×600=600×(209-

201)=600×8=4800

5. 123×(53-50)+3×147=

123×3+3×147=3×(123+147)=

3×270=810

Sper ca te-am ajutat!

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