Question

Calculati in doua moduri:
a)84*(26+318)
b)(148+39)*419
c)68*(47+38-25)
d)96*(517-125)
e)(786-104)*317
f)(167-89+)*52
Va aduc aminte inca odata ca trebuie prin 2 moduri.
primul raspuns correct primeste coronita!

Answer 1

a)
84*(26+318)=
84*344=
28 896

84*(26+318)=
84*26+84*318=
2 184 + 26 712 =
28 896


b)
(148+39)*419=
187*419=
78 353

(148+39)*419=
148*419+39*419=
62 012+16 341=
78 353


c)
68*(47+38-25)=
68*(85-25)=
68*60=
4 080

68*(47+38-25)=
68*47+68*38-68*25=
3 196 + 2 584 - 1 700 =
5 780 - 1 700=
4 080


d)
96*(517-125)=
96*392=
37 632

96*(517-125)=
96*517-96*125=
49 632 - 12 000=
37 632


e)
(786-104)*317=
682*317=
216 194

(786-104)*317=
786*317-104*317=
249 162-32 968=
216 194


f)
(167-89+)*52=
78*52=
4 056

(167-89+)*52=
167*52-89*52=
8 684 - 4 628=
4 056