Question

Calculati in Q:

(2intreg 3supra4 - 3intreg 1supra2) : (x-2)= 11supra8

Answer 1

2 intregi 3/4 = (2 × 4 + 3)/4 = 11/4

3 intregi 1/2 = (3 × 2 + 1)/2 = 7/2

(11/4 - 7/2) : (x - 2) = 11/8

(11 - 7×2)/4 : (x - 2) = 11/8

(11 - 14)/4 : (x - 2) = 11/8

- 3/4 × 1/(x - 2) = 11/8

- 3/[4×(x-2)] = 11/8

- 3/ (4x - 8) = 11/8

11 × (4x - 8) = - 3 × 8

44x - 88 = - 24

44x = - 24 + 88

44x = 64

x = 64/44

x = 16/11

x = 1 intreg 5/11
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