Question

Calculati limita sirului:
$\lim_{n \to \infty} \dfrac{3^{n}+2*4^{n}-2^{n+1} }{2^{2n}-2^{n}+3^{n+1} }$

Answer 1

Răspuns:

Explicație pas cu pas:

L= lim n->inf((3/4)^n +2*(4/4)^n - 2*(2/4)^n)/((4/4)^n-(2/4)^n +3*(3/4)^n )=

 = (0 +2 -2*0)(1 -0 +3*0) = 2/1 = 2