Question

Calculati masa solutiei de hidroxid de potasiu care reactioneaza cu 196g H2So4 solutia avand concentratia 49%​

Answer 1

Răspuns:

x_____196 g

KOH + H2SO4 ==> K2SO4 + H2O

56g___98g

$c = \frac{md \times 100}{ms} = > \\ \\ md = \frac{c \times ms}{100} = \\ \\ = \frac{196 \times 49}{100} = \\ \\ = 96.04 \: g$

M KOH = A K + A O + A H =

= 39 + 16 + 1

= 56 g pe mol

M H2SO4= 2×A H + A S + 4×A O

= 2×1 + 32 + 4×16

= 98 g pe mol

$x = \frac{56 \times 196}{98} = \\ \\ = 112g$

$c = \frac{md \times 100}{ms} = > \\ \\ ms = \frac{md \times 100}{c} = \\ \\ = \frac{112 \times 100}{49} = \\ \\ = 228.57g$

Succes!