Question

calculati media aritmetică a trei nr. , stiind ca doua cate doua au media aritmetică:11;36;32. dau coroana

Answer 1

(a+b+c)÷3=?
(a+b)÷2=11
(a+c)÷2=32
(b+c)÷2=36

[2×(a+b+c)]÷2=11+32+36=79
a+b+c=79

(a+b+c)÷3=79÷3=26,(3)

Answer 2

a+b / 2 = 11
b+c / 2 = 36
c+a / 2 = 32 si le adunam
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2(a+b+c)/2 =79 ⇔ a+b+c = 79
Ma= (a+b+c)/3 = 79/3 = 26si1/3 sau = 26,(3)