Question

Calculati media aritmetica a tuturor numerelor naturale X care verifica inegalitatea.
3,4*X<_18,02

Answer 1

X < 5,3 ⇒ x ∈ {0,1,2,3,4,5}
M = (1+2+3+4+5)/6 = 15/6 = 5/2 = 2,5

Answer 2

$x | 3,4*x \leq 18,02, x \ apartine \ multimii \ 0,1,2,3,4,5;$
$M _{a} = \frac{0+1+2+3+4+5}{6} = \frac{15}{6} ^{(3} = \frac{5}{2} =\boxed{\bold{2,5}}.$