Question

Calculati media aritmetica ponderata a numerelor:

1 supra 3;1 supra 6; 3 supra 8 cu ponderile 2;3 si 4.

Answer 1

$map = \frac{\frac{1}{3}* 2 + \frac{1}{6} *3 + \frac{3}{8}*4}{2+3+4}= \frac{ \frac{2}{3}^{(2} + \frac{1}{2}^{(3}+ \frac{3}{2}^{(3}}{9} } \\ \\ map=\frac{ \frac{4+3+9}{6} }{9}= \frac{16}{6} * \frac{1}{9} \\ \\ \boxed{map=\frac{16}{54}= 0,(296)}$