Question

calculati media aritmetica ponderata a numerelor

a) 1,2 ; 2,5 cu ponderile 5, respectiv 2
b) 3 supra 5 ; 4 supra 9 ; 5 supra 7 cu ponderile 10,9,respectiv 14

Answer 1

$a)m_{p1}=\frac{1,2*5+2,5*2}{2+5}$

$m_{p1}=\frac{6+5}{2+5}$

$m_{p1}=\frac{11}{7}$

$b)m_{p2}=\frac{\frac{3}{5}*10+\frac{4}{9}*9+\frac{5}{7}*14}{10+9+14}$

$m_{p2}=\frac{6+4+10}{33}$

$m_{p2}=\frac{20}{33}$

$Formula \ pentru \ media \ aritmetica \ ponderata:$

$Fie \ nr \ a_1,a_2,a_3,....,a_k \ cu \ ponderile \ k_1,$$k_2,k_3,...,k,atunci \ media \ aritmetica \ ponderata \ este:$

$m_p=\frac{a_1*k_1+a_2*k_2+...+a_k*k}{k_1+k_2+k_3+...+k}$