Question

Calculati media geometrica a numerelor a = | 2√2-3 | si b= (1+√2)²

Answer 1

$2\sqrt2-3<0\Rightarrow |2\sqrt2-3|=3-2\sqrt2$

$b=(1+\sqrt2)^2=3+2\sqrt2$

$m_g=\sqrt{ab}=\sqrt{(3-2\sqrt2)(3+2\sqrt2)}=\sqrt{9-8}=1$

Answer 2

(2√2)²=8
3²=9⇒se inverseaza numerele astfel din 2√2-3 devine 3-2√2
media geometrica= √axb
axb= 3-2√2 x 1+2√2+2
axb = (3-2√2)(3+2√2)
a x b=3²-2√2²
a x b= 9-8
a x b=1
media geometrica= √1=1