Question

Calculati media geometrica a numerelor: x=modul 6√3+3√11 modul si y=modul 3√11 -6√3

Answer 1

x=|6√3+3√11| ⇒ x=6√3+3√11
y=|3√11-6√3| ⇒ y=6√3-3√11

$Mg = \sqrt{x*y} \\ \\ Mg = \sqrt{(6 \sqrt{3} +3 \sqrt{11}) * \{(6 \sqrt{3} -3 \sqrt{11}) } } \\ \\ Mg = \sqrt{108-99} \\ \\ Mg= \sqrt{9} \\ \\ Mg = 3$

Sper ca te-am ajutat.

Mg - media geometrica

Answer 2

x=|6√3+3√11|
y=|3√11-6√3|
Media geometrica inseamna $\sqrt{a*b}$
3√11=√99
6√3=√36*3=√108
cum 108>99=>6√3>3√11=>|3√11-6√3|=6√3-3√11

$\sqrt{(6√3+3√11)*(6√3-3√11)}$=.$\sqrt{36*3-9*11}$=$\sqrt{9}$=3