Calculați numărul de molecule din:490 kg acid sulfuric
44,8 l metan
0,5 kmoli apă
73 g acid clorhidric
224 m cubi dioxid de sulf.
Răspunsuri la întrebare
Răspuns:
Explicație:
44,8 LCH4
n= 44,8 L : 22,4L/moli= 2moli CH4
1mol CH4----------------6,022.10²³ molecule CH4
2moli----------------------------x
x= 2 . 6,022.10²³ = 12,044.10²³molecule CH4
490 kg H2SO4 = 490000g
n= 490000g : 98 g/moli= 5000moli H2 SO4
1mol H2SO4---------------6,022.10²³ molecule H2SO4
5000moli--------------------------y
y= 5000. 6,022.10²³ molecule H2SO4=
0,5kmoli H2O = 500moli H2O
1mol H2O---------------6,022.10²³molecule H2 O
500moli --------------------------z
z= 500. 6,022.10²³molecule H2O=
73 g HCl
n= 73g : 36,5g/moli= 2moli HCl
1mol HCl------------------6,022.10²³molecule HCl
2moli ------------------------------x
x= 2 . 6,022.10²³ molecule HCl=
224m³SO2
n= 224m³ : 22,4 m³/kmoli=10 kmoli SO2= 10000moli SO2
1mol SO2-------------------6,022.10²³molecule SO2
10000moli ----------------------y
y= 10000. 6.022.10²³molecule SO2=