Question

Calculati procentul de carbon din benzen(C6H6) si masa de clor din 10 moli de CHCl3.

Answer 1

μ C6H6 =12×6+6=78

Daca in 78g.............72g C

Atunci in 100g......x g C

==>x=72×100/78=92,30% gCarbon

10 moli de CHCl3

m =Nr de moli×μ

μ Cl=35,5×3=106,5

m Cl=10×106.5=1065